improbable
Mission Improbable
Calculate some probabilities.
Notes
I used integer percentages rather than decimals for my inputs.
Probably more time was spent thinking up a design than coding. My main motivation was to think through how I, as a human, would work through the example problem given (input/sample2).
The notation:
P(A)
for the probability of an event happening.P(!A)
for the probability of an event not happening.P(A & B)
for the probability of both events happening.P(A + B)
for the probability of at least one event happening (notP(A | B)
for the potential to confusion with conditional probability, though conditional probability is not discussed here).
The thought process:
- Given that
P(!A & !B & !C) = 0.1
, I would knowP(A + B + C) = 1.0 - 0.1 = 0.9
- Given that
P(A & !B & !C) = 0.13
and the above inference, I would knowP(B + C) = 0.9 - 0.13 = 0.77
. P(B + C) = P(B) + P(C) - P(B & C)
, meaning0.77 = 0.7 + 0.27 - P(B & C)
The useful part was to see that when we learn about P(E)
and know about P(E')
where E
is a subset of E'
, we can infer P(E' - E)
or P(E' & !E)
. This is the general case of "When we learn P(E), we can infer P(!E)
" - the specific case here is where E' = S
. Similarly, when we learn P(E)
and know about a P(E')
that is mutually exclusive with E
, we can infer P(E + E')
. The rule about P(B + C) = P(B) + P(C) - P(B & C)
did not need to be specifically implemented.
Source
improbable
- 1
- 0
- 0
- 0
- 0
- about 8 years ago
- October 10, 2016
Sun, 24 Nov 2024 13:52:27 GMT